A uniform conductor of resistance R is cut in | vedclass

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(C) Resistance of each piece $= \frac{R}{20} \Omega$. Equivalent resistance of $10$ such pieces connected in series is $R_1 = 10 	imes \frac{R}{20} =

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$\frac{101 R}{200}$

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(C) Resistance of each piece $= \frac{R}{20} \Omega$. Equivalent resistance of $10$ such pieces connected in series is $R_1 = 10 	imes \frac{R}{20} = \frac{R}{2}$. Similarly,equivalent resistance of $10$ such pieces connected in parallel is $\frac{1}{R_2} = \frac{1}{R/20} + \dots (10 	ext{ times}) = \frac{10}{R/20} = \frac{200}{R}$,so $R_2 = \frac{R}{200}$. Now,$R_1$ and $R_2$ are connected in series,so the total resistance is $R_{eq} = R_1 + R_2 = \frac{R}{2} + \frac{R}{200} = \frac{100R + R}{200} = \frac{101R}{200}$.

$A$ uniform conductor of resistance $R$ is cut into $20$ equal pieces. Half of them are joined in series and the remaining half of them are connected in parallel. If the two combinations are joined in series,the effective resistance of all the pieces is

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