(C) During charging,the current $I$ in the circuit is given by the formula: $I = \frac{V_{supply} - E}{R + r}$.Here,$V_{supply} = 160 \ V$,$E = 10 \ V

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(C) During charging,the current $I$ in the circuit is given by the formula: $I = \frac{V_{supply} - E}{R + r}$.Here,$V_{supply} = 160 \ V$,$E = 10 \ V$,$R = 24 \ \Omega$,and $r = 1 \ \Omega$.Substituting the values: $I = \frac{160 - 10}{24 + 1} = \frac{150}{25} = 6 \ A$.The terminal voltage $V$ of the battery during charging is given by $V = E + Ir$.Substituting the values: $V = 10 + (6 \times 1) = 10 + 6 = 16 \ V$.

Class 12 Physics Current Electricity Circuit Solving for current and Voltage

Medium

$A$ $DC$ supply of $160 \ V$ is used to charge a battery of $EMF$ $10 \ V$ and internal resistance $1 \ \Omega$ by connecting a series resistance of $24 \ \Omega$. The terminal voltage of the battery during charging is (in $V$)

AP EAMCET 2025 All AP EAMCET

A
$8$
B
$12$
C
$16$
D
$4$

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Circuit Solving for current and Voltage

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$A$ $DC$ supply of $160 \ V$ is used to charge a battery of $EMF$ $10 \ V$ and internal resistance $1 \ \Omega$ by connecting a series resistance of $24 \ \Omega$. The terminal voltage of the battery during charging is (in $V$)

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