$A$ compound $A$ is used in paints instead of salts of lead. Compound $A$ is obtained when a white compound $B$ is strongly heated. The compound $B$ is insoluble in water but dissolves in $NaOH$ solution,forming a solution of compound $C$. The compound $A$ on heating with coke gives a volatile metal $D$ and a gas $E$ which burns with a blue flame. Identify the possible species $D$ and $C$ respectively.
- A$D - Hg, C - Hg(OH)_2$
- B$D - Cd, C - Na_2[CdO_2]$
- C$D - Zn, C - Na_2ZnO_2$
- D$D - Zn, C - Zn(OH)_2$
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Which of the following elements does not form a monoxide?
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Which of the following exhibits moderate electrical conductivity?
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View SolutionFind $A$,$B$ and $C$ in the following reactions:
$NH_3 + A + CO_2 \rightarrow (NH_4)_2CO_3$
$(NH_4)_2CO_3 + H_2O + B \rightarrow 2NH_4HCO_3$
$NH_4HCO_3 + NaCl \rightarrow NH_4Cl + C$
$NH_3 + A + CO_2 \rightarrow (NH_4)_2CO_3$
$(NH_4)_2CO_3 + H_2O + B \rightarrow 2NH_4HCO_3$
$NH_4HCO_3 + NaCl \rightarrow NH_4Cl + C$
Consider the following reaction:
$R_2SiCl_2 + H_2O \to (1) \xrightarrow{\text{polymerisation}} (2)$
Compound $(2)$ in the above reaction is:
$R_2SiCl_2 + H_2O \to (1) \xrightarrow{\text{polymerisation}} (2)$
Compound $(2)$ in the above reaction is:
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