A straight conductor of length 4 ~m moves at | vedclass

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(D) The induced electromotive force (emf) in a moving conductor is given by the formula:$e = B v l \sin 	heta$Where:$B = 0.1 ~Wb/m^2$ (Magnetic field

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$2$

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(D) The induced electromotive force (emf) in a moving conductor is given by the formula:$e = B v l \sin 	heta$Where:$B = 0.1 ~Wb/m^2$ (Magnetic field induction)$v = 10 ~m/s$ (Velocity of the conductor)$l = 4 ~m$ (Length of the conductor)$	heta = 30^{\circ}$ (Angle between the conductor and the magnetic field)Substituting the values into the formula:$e = 0.1 	imes 10 	imes 4 	imes \sin(30^{\circ})$$e = 0.1 	imes 10 	imes 4 	imes 0.5$$e = 1 	imes 4 	imes 0.5$$e = 2 ~V$Thus,the induced emf is $2 ~V$.

$A$ straight conductor of length $4 ~m$ moves at a speed of $10 ~m/s$. When the conductor makes an angle of $30^{\circ}$ with the direction of the magnetic field of induction $0.1 ~Wb/m^2$,the induced emf is: (in $~V$)

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