A particle of mass 2.2 times 10^{-30} ,kg and | vedclass

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(D) Given: Mass $m = 2.2 	imes 10^{-30} \,kg$,Charge $q = 1.6 	imes 10^{-19} \,C$,Velocity $v = 10 \,km/s = 10^4 \,m/s$,Radius $r = 2.8 \,cm = 2.8 \

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$1.56$

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(D) Given: Mass $m = 2.2 	imes 10^{-30} \,kg$,Charge $q = 1.6 	imes 10^{-19} \,C$,Velocity $v = 10 \,km/s = 10^4 \,m/s$,Radius $r = 2.8 \,cm = 2.8 	imes 10^{-2} \,m$,Turns per unit length $n = 25 \,turns/cm = 2500 \,turns/m$.For a charged particle in a magnetic field,the radius of the circular path is given by $r = \frac{mv}{Bq}$.The magnetic field inside a solenoid is $B = \mu_0 n I$.Substituting $B$ into the radius formula: $r = \frac{mv}{(\mu_0 n I)q}$.Rearranging for current $I$: $I = \frac{mv}{\mu_0 n q r}$.Substituting the values: $I = \frac{2.2 	imes 10^{-30} 	imes 10^4}{4\pi 	imes 10^{-7} 	imes 2500 	imes 1.6 	imes 10^{-19} 	imes 2.8 	imes 10^{-2}}$.$I = \frac{2.2 	imes 10^{-26}}{4 	imes 3.14159 	imes 10^{-7} 	imes 2500 	imes 1.6 	imes 10^{-19} 	imes 2.8 	imes 10^{-2}} \approx 1.56 	imes 10^{-3} \,A = 1.56 \,mA$.

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