A solenoid has a length of 1 ,m and a cross-s | vedclass

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(A) The self-inductance $L$ of a solenoid is given by the formula:$L = \frac{\mu_0 N^2 A}{l}$Given values:Number of turns, $N = 5000$Length, $l = 1 \,

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$0.2$

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(A) The self-inductance $L$ of a solenoid is given by the formula:$L = \frac{\mu_0 N^2 A}{l}$Given values:Number of turns, $N = 5000$Length, $l = 1 \,m$Area, $A = 0.02 \,m^2$Permeability of free space, $\mu_0 = 4 \pi 	imes 10^{-7} \,T \cdot m/A$Substituting these values into the formula:$L = \frac{4 \pi 	imes 10^{-7} 	imes (5000)^2 	imes 0.02}{1}$$L = 4 \pi 	imes 10^{-7} 	imes 25,000,000 	imes 0.02$$L = 4 \pi 	imes 10^{-7} 	imes 500,000$$L = 4 \pi 	imes 0.05 = 0.2 \pi \,H$

$A$ solenoid has a length of $1 \,m$ and a cross-sectional area of $0.02 \,m^2$. If the number of turns in the solenoid is $5000$, then the self-inductance of the solenoid is: (in $\pi \,H$)

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