$A$ commercial sample of $H_2O_2$ marked as $100$ volume hydrogen peroxide means:
- A$1 \ mL$ of $H_2O_2$ will give $100 \ mL$ of $O_2$ at $STP$
- B$1 \ L$ of $H_2O_2$ will give $100 \ mL$ of $O_2$ at $STP$
- C$1 \ L$ of $H_2O_2$ will give $22.4 \ L$ of $O_2$ at $STP$
- D$1 \ mL$ of $H_2O_2$ will give $1 \ mole$ of $O_2$ at $STP$
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Similar Questions
$H_2O_2$ is
Medium
View SolutionThe correct statements among the following are
$i$. Saline hydrides produce $H_2$ gas when reacted with water
$ii$. Presently $\sim 77 \%$ of the industrial dihydrogen is produced from coal
$iii$. Commercially marketed $H_2O_2$ contains $3 \% H_2O_2$
$i$. Saline hydrides produce $H_2$ gas when reacted with water
$ii$. Presently $\sim 77 \%$ of the industrial dihydrogen is produced from coal
$iii$. Commercially marketed $H_2O_2$ contains $3 \% H_2O_2$
Match List $I$ with List $II$ and select the correct answer using the codes given below the lists:
$A$. Peroxide $1$. $C_3O_2$ $B$. Superoxide $2$. $PbO_2$ $C$. Dioxide $3$. $KO_2$ $D$. Suboxide $4$. $H_2O_2$
| $A$. Peroxide | $1$. $C_3O_2$ |
| $B$. Superoxide | $2$. $PbO_2$ |
| $C$. Dioxide | $3$. $KO_2$ |
| $D$. Suboxide | $4$. $H_2O_2$ |
Medium
View SolutionTo an aqueous solution of $AgNO_3$,some $NaOH_{(aq)}$ is added until a brown precipitate is obtained. To this,$H_2O_2$ is added dropwise. The precipitate turns black with the evolution of $O_2$. The black precipitate is:
Medium
View SolutionThe molecular mass of hydrogen peroxide is $34$. What is the unit of molar mass?
Easy
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