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(A) The mean kinetic energy per molecule of an ideal gas is given by the formula $\bar{E} = \frac{3}{2} K_B T$,where $K_B$ is the Boltzmann constant a

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$1: 1$

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(A) The mean kinetic energy per molecule of an ideal gas is given by the formula $\bar{E} = \frac{3}{2} K_B T$,where $K_B$ is the Boltzmann constant and $T$ is the absolute temperature.Since the gases are in the same vessel,they are in thermal equilibrium,meaning they are at the same temperature $T$.Because the mean kinetic energy $\bar{E}$ depends only on the temperature $T$ and is independent of the mass or nature of the gas molecules,the ratio of the mean kinetic energies of hydrogen and oxygen is $1: 1$.

$A$ vessel contains a mixture of hydrogen and oxygen gases in the ratio of their masses equal to $1: 5$. The ratio of mean kinetic energies of the two gases is

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