(A) Given: Number of turns $N = 200$,radius $r = 20 \ cm = 0.2 \ m$,and current $I = 5 \ A$.The magnetic field $B$ at the centre of a circular coil is

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

(A) Given: Number of turns $N = 200$,radius $r = 20 \ cm = 0.2 \ m$,and current $I = 5 \ A$.The magnetic field $B$ at the centre of a circular coil is given by the formula:$B = \frac{\mu_0 NI}{2r}$Substituting the values:$B = \frac{(4\pi \times 10^{-7} \ T \cdot m/A) \times 200 \times 5}{2 \times 0.2 \ m}$$B = \frac{4 \times 3.14159 \times 10^{-7} \times 1000}{0.4}$$B = \frac{12.566 \times 10^{-4}}{0.4}$$B = 31.4159 \times 10^{-4} \ T = 3.14 \times 10^{-3} \ T$.

Class 12 Physics Moving Charges and Magnetism Biot-Savart's Law and its application

Medium

$A$ tightly wound coil of $200$ turns and of radius $20 \ cm$ carries a current of $5 \ A$. The magnetic field at the centre of the coil is:

AP EAMCET 2024 All AP EAMCET

A
$3.14 \times 10^{-3} \ T$
B
$3.14 \times 10^{-2} \ T$
C
$6.28 \times 10^{-4} \ T$
D
$6.28 \times 10^{-3} \ T$

Explore More

Browse All

Question Bank

All Subjects

Class 12 Questions

Class 12

Physics Questions

Chapter

Moving Charges and Magnetism

Subtopic

Biot-Savart's Law and its application

Previous Year

AP EAMCET 2024 Paper All AP EAMCET years →

Two long straight parallel conductors $10 \text{ cm}$ apart,carry equal currents of magnitude $3 \text{ A}$ in the same direction. Then,the magnetic induction at a point midway between them is

EasyAP EAMCET 2015

View Solution

In a hydrogen atom,an electron is revolving at $6.6 \times 10^{15} \text{ rev/s}$ around the nucleus in an orbit of radius $0.47 \text{ Å}$. The magnetic field induction produced at the centre of the orbit is nearly: (in $\text{ Wb m}^{-2}$)

DifficultAP EAMCET 2024

View Solution

$A$ straight wire of finite length carrying current $I$ subtends an angle of $60^{\circ}$ at point $P$ as shown. The magnetic field at $P$ is

Medium

View Solution

In terms of basic units of mass $(M)$,length $(L)$,time $(T)$ and charge $(Q)$,the dimensions of magnetic permeability of vacuum $(\mu_0)$ would be

MediumAIIMS 2015

View Solution

The magnetic field due to a current-carrying circular loop of radius $5 \ cm$ at a point on the axis at a distance of $12 \ cm$ from the centre is $250 \ \mu T$. The magnetic field at the centre of the loop is (in $\mu T$)

MediumAP EAMCET 2021

View Solution

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial

For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free

For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo

$A$ tightly wound coil of $200$ turns and of radius $20 \ cm$ carries a current of $5 \ A$. The magnetic field at the centre of the coil is:

Similar Questions

Two long straight parallel conductors $10 \text{ cm}$ apart,carry equal currents of magnitude $3 \text{ A}$ in the same direction. Then,the magnetic induction at a point midway between them is

In a hydrogen atom,an electron is revolving at $6.6 \times 10^{15} \text{ rev/s}$ around the nucleus in an orbit of radius $0.47 \text{ Å}$. The magnetic field induction produced at the centre of the orbit is nearly: (in $\text{ Wb m}^{-2}$)

$A$ straight wire of finite length carrying current $I$ subtends an angle of $60^{\circ}$ at point $P$ as shown. The magnetic field at $P$ is

In terms of basic units of mass $(M)$,length $(L)$,time $(T)$ and charge $(Q)$,the dimensions of magnetic permeability of vacuum $(\mu_0)$ would be

The magnetic field due to a current-carrying circular loop of radius $5 \ cm$ at a point on the axis at a distance of $12 \ cm$ from the centre is $250 \ \mu T$. The magnetic field at the centre of the loop is (in $\mu T$)

Vedclass Test Series

Exam Paper Generator

Online Exam Module