ABC is a triangle in which angle C is a right | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) Since $\angle C = 90^{\circ}$,the hypotenuse $AB$ must be the diameter of the circumcircle of $	riangle ABC$ because the angle subtended by the d

Vedclass · Accepted Answer

$x^2 + y^2 = 25$

Vedclass · Answer

(B) Since $\angle C = 90^{\circ}$,the hypotenuse $AB$ must be the diameter of the circumcircle of $	riangle ABC$ because the angle subtended by the diameter at the circumference is a right angle.The equation of a circle with diameter endpoints $(x_1, y_1)$ and $(x_2, y_2)$ is given by $(x - x_1)(x - x_2) + (y - y_1)(y - y_2) = 0$.Substituting the coordinates $A(-3, 4)$ and $B(3, -4)$:$(x - (-3))(x - 3) + (y - 4)(y - (-4)) = 0$$(x + 3)(x - 3) + (y - 4)(y + 4) = 0$$(x^2 - 9) + (y^2 - 16) = 0$$x^2 + y^2 - 25 = 0$$x^2 + y^2 = 25$.

$ABC$ is a triangle in which angle $C$ is a right angle. If the coordinates of $A$ and $B$ are $(-3, 4)$ and $(3, -4)$ respectively,then the equation of the circumcircle of triangle $ABC$ is

Similar Questions

The equation of a circle whose centre lies at the point $(-2, 1)$ and which passes through the point $(4, 3)$ is:

$A$ circle touches the $y$-axis at the point $(0, 4)$ and cuts the $x$-axis in a chord of length $6$ units. The radius of the circle is

The equation of a circle which touches the $x$-axis and whose centre is $(1, 2)$ is

If $z=x+iy$,then the centre of the circle $\left|\frac{z-3}{z-2i}\right|=2$ is

The equation of the circle concentric with the circle $x^2+y^2-6x+12y+15=0$ and having double its area is:

Vedclass Test Series

Exam Paper Generator

Online Exam Module