int frac{sec x}{sqrt{sin (2 x + theta) + sin | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) Given $I = \int \frac{\sec x}{\sqrt{\sin (2 x + 	heta) + \sin 	heta}} d x$Using the formula $\sin C + \sin D = 2 \sin (\frac{C + D}{2}) \cos (\f

Vedclass · Accepted Answer

$\sqrt{2 (	an x + 	an 	heta) \sec 	heta} + c$

Vedclass · Answer

(B) Given $I = \int \frac{\sec x}{\sqrt{\sin (2 x + 	heta) + \sin 	heta}} d x$Using the formula $\sin C + \sin D = 2 \sin (\frac{C + D}{2}) \cos (\frac{C - D}{2})$:$\Rightarrow I = \int \frac{\sec x}{\sqrt{2 \sin (\frac{2 x + 2 	heta}{2}) \cos (\frac{2 x + 	heta - 	heta}{2})}} d x$$\Rightarrow I = \int \frac{\sec x}{\sqrt{2 \sin (x + 	heta) \cos x}} d x$$\Rightarrow I = \int \frac{\sec x}{\sqrt{2 (\sin x \cos 	heta + \cos x \sin 	heta) \cos x}} d x$Divide numerator and denominator by $\cos x$ inside the square root:$\Rightarrow I = \int \frac{\sec x}{\sqrt{2 \cos^2 x (	an x \cos 	heta + \sin 	heta)}} d x$$\Rightarrow I = \int \frac{\sec x}{\sqrt{2} \cos x \sqrt{	an x \cos 	heta + \sin 	heta}} d x$$\Rightarrow I = \frac{1}{\sqrt{2}} \int \frac{\sec^2 x}{\sqrt{	an x \cos 	heta + \sin 	heta}} d x$Let $t = 	an x \cos 	heta + \sin 	heta$,then $dt = \sec^2 x \cos 	heta d x$,so $\sec^2 x d x = \frac{dt}{\cos 	heta}$.$\Rightarrow I = \frac{1}{\sqrt{2} \cos 	heta} \int t^{-1/2} dt$$\Rightarrow I = \frac{1}{\sqrt{2} \cos 	heta} \cdot 2 t^{1/2} + C$$\Rightarrow I = \sqrt{\frac{2}{\cos^2 	heta}} \sqrt{	an x \cos 	heta + \sin 	heta} + C$$\Rightarrow I = \sqrt{2 \sec^2 	heta (	an x \cos 	heta + \sin 	heta)} + C$$\Rightarrow I = \sqrt{2 \sec 	heta (	an x + 	an 	heta)} + C$

$\int \frac{\sec x}{\sqrt{\sin (2 x + \theta) + \sin \theta}} d x =$

Similar Questions

$\int \frac{f(x) g^{\prime}(x)-f^{\prime}(x) g(x)}{f(x) g(x)} \times [\log g(x)-\log f(x)] \, dx$ is equal to

Evaluate the integral: $\int \frac{(x+1)(x+\log x)^2}{x} dx$

Let $I(x)=\int \frac{6}{\sin ^2 x(1-\cot x)^2} d x$. If $I(0)=3$,then $I\left(\frac{\pi}{12}\right)$ is equal to :

The value of $\int \frac{\sin^3 x}{(\cos^4 x + 3 \cos^2 x + 1) \tan^{-1}(\sec x + \cos x)} dx$ is

Integrate the function: $\frac{\sec ^{2} x}{\sqrt{\tan ^{2} x+4}}$

Vedclass Test Series

Exam Paper Generator

Online Exam Module