$H_2O_2$ reduces $KMnO_4$ in acidic medium to '$x$' and in basic medium to '$y$'. What are $x$ and $y$?
- A$x=MnO_2, \quad y=Mn^{2+}$
- B$x=Mn^{2+}, \quad y=MnO_2$
- C$x=MnO_4^{2-}, y=Mn^{2+}$
- D$x=MnO_2, \quad y=MnO_4^{2-}$
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