$A$ Zener diode is made by
- Aheavily doping both $p$- and $n$-sides of a $p-n$ junction diode
- Bheavily doping the $p$-side and lightly doping the $n$-side of a $p-n$ junction diode
- Clightly doping the $p$-side and heavily doping the $n$-side of a $p-n$ junction diode
- Dlightly doping both $p$- and $n$-sides of a $p-n$ junction diode
Explore More
Similar Questions
The circuit shown below is working as an $8\; V\; dc$ regulated voltage source. When $12 \; V$ is used as input, the power dissipated (in $mW$) in each diode is (considering both zener diodes are identical).
In the diagram shown,the Zener diode has a reverse breakdown voltage of $V_Z$. The current through the load resistance $R_L$ is $I_L$. The current through the Zener diode is
MediumKCET 2024
View Solution$A$ Zener diode is specified as having a breakdown voltage of $9.1 \;V$,with a maximum power dissipation of $364 \;mW$. What is the maximum current $(mA)$ the diode can handle?
Zener breakdown takes place if
Easy
View SolutionWhen a Zener diode is used as a regulator with a Zener voltage of $10 \, V$, nearly five times the load current passes through the Zener diode. What should be the series resistance for the Zener diode if the load resistance is $2 \, k\Omega$ and the unregulated voltage supplied is $16 \, V$?
Vedclass Products
For Students
Vedclass Test Series
Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.
Start Free TrialFor Teachers
Exam Paper Generator
Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.
Try FreeFor Institutes
Online Exam Module
Live online exams with unlimited students, 360° analytics & white-label branding.
See Demo