10 g of NaOH is dissolved in 500 mL of aque | vedclass

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(D) Molarity $(M)$ is defined as the number of moles of solute per liter of solution.Step $1$: Calculate the number of moles of $NaOH$.Moles of $NaOH

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$0.5 \ M$

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(D) Molarity $(M)$ is defined as the number of moles of solute per liter of solution.Step $1$: Calculate the number of moles of $NaOH$.Moles of $NaOH = \frac{	ext{Given mass}}{	ext{Molar mass}} = \frac{10 \ g}{40 \ g \ mol^{-1}} = 0.25 \ mol$.Step $2$: Convert the volume of the solution to liters.Volume $= 500 \ mL = 0.5 \ L$.Step $3$: Calculate Molarity.Molarity $= \frac{	ext{Moles of solute}}{	ext{Volume of solution in } L} = \frac{0.25 \ mol}{0.5 \ L} = 0.5 \ M$.

$10 \ g$ of $NaOH$ is dissolved in $500 \ mL$ of aqueous solution. Calculate the molarity of this solution? (Given,formula weight of $NaOH = 40$)

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