A hunter fired a metallic bullet of mass m k | vedclass

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(A) The kinetic energy of the bullet is converted into heat. Since $\frac{1}{4}$ of the heat is absorbed by the obstacle,$\frac{3}{4}$ of the kinetic

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$410$

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(A) The kinetic energy of the bullet is converted into heat. Since $\frac{1}{4}$ of the heat is absorbed by the obstacle,$\frac{3}{4}$ of the kinetic energy is used to heat and melt the bullet.The energy balance equation is: $\frac{3}{4} (\frac{1}{2} m v^2) = m s \Delta 	heta + m L$.Given: $s = 0.03 \ cal \ g^{-1} {}^{\circ} C^{-1} = 0.03 	imes 4200 \ J \ kg^{-1} K^{-1} = 126 \ J \ kg^{-1} K^{-1}$.$\Delta 	heta = 600 \ K - 300 \ K = 300 \ K$.$L = 6 \ cal \ g^{-1} = 6 	imes 4200 \ J \ kg^{-1} = 25200 \ J \ kg^{-1}$.Substituting the values: $\frac{3}{8} v^2 = (126 	imes 300) + 25200$.$\frac{3}{8} v^2 = 37800 + 25200 = 63000$.$v^2 = \frac{63000 	imes 8}{3} = 21000 	imes 8 = 168000$.$v = \sqrt{168000} \approx 409.88 \ ms^{-1} \approx 410 \ ms^{-1}$.

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