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(A) Given:Temperature of the body, $T_1 = 3000 \,K$Wavelength of maximum energy emission for the body, $\lambda_1 = 9660 Å$Wavelength of maximum energ

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$5855$

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(A) Given:Temperature of the body, $T_1 = 3000 \,K$Wavelength of maximum energy emission for the body, $\lambda_1 = 9660 Å$Wavelength of maximum energy emission for the sun, $\lambda_2 = 4950 Å$According to Wien's displacement law, the product of the wavelength of maximum emission and the absolute temperature is constant:$\lambda_1 T_1 = \lambda_2 T_2$Rearranging to find the temperature of the sun $(T_2)$:$T_2 = \frac{\lambda_1 T_1}{\lambda_2}$Substituting the given values:$T_2 = \frac{9660 Å 	imes 3000 \,K}{4950 Å}$$T_2 = \frac{28980000}{4950} \,K$$T_2 \approx 5854.54 \,K$Rounding to the nearest whole number, we get $T_2 \approx 5855 \,K$.

$A$ body at $3000 \,K$ emits maximum energy at a wavelength of $9660 Å$. If the sun emits maximum energy at a wavelength of $4950 Å$, what would be the temperature of the sun (in $\,K$)?

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