(D) According to Stefan-Boltzmann Law,the power $P$ radiated by a black body is given by $P = \sigma A T^4$.Given:$\sigma = 5.67 \times 10^{-8} ~W m^{

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(D) According to Stefan-Boltzmann Law,the power $P$ radiated by a black body is given by $P = \sigma A T^4$.Given:$\sigma = 5.67 \times 10^{-8} ~W m^{-2} K^{-4}$$A = 200 ~mm^2 = 200 \times 10^{-6} ~m^2$$T = 727^{\circ} C = 727 + 273 = 1000 ~K$Substituting these values into the formula:$P = (5.67 \times 10^{-8}) \times (200 \times 10^{-6}) \times (1000)^4$$P = 5.67 \times 10^{-8} \times 2 \times 10^{-4} \times 10^{12}$$P = 5.67 \times 2 \times 10^{-12} \times 10^{12}$$P = 11.34 ~J/s$.

Class 11 Chemistry Data Entry - Chemistry Level 0 of all question bank

$A$ very small hole in an electric furnace is used for heating metals. The hole nearly acts as a black body. The area of the hole is $200 ~mm^2$. To keep a metal at $727^{\circ} C$,the heat energy flowing through this hole per second,in joules,is $\left(\sigma = 5.67 \times 10^{-8} ~W m^{-2} K^{-4}\right)$.

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A
$22.68$
B
$2.268$
C
$1.134$
D
$11.34$

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