Two electric bulbs rated P_1 text{ watt}, V t | vedclass

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(C) The power rating of a bulb is given by $P = \frac{V^2}{R}$,where $V$ is the rated voltage and $R$ is the resistance of the bulb.For the first bulb

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$(P_1 + P_2) 	ext{ watt}$

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(C) The power rating of a bulb is given by $P = \frac{V^2}{R}$,where $V$ is the rated voltage and $R$ is the resistance of the bulb.For the first bulb,$R_1 = \frac{V^2}{P_1}$.For the second bulb,$R_2 = \frac{V^2}{P_2}$.When connected in parallel,the total power $P_{	ext{total}}$ is the sum of the individual powers consumed by each bulb.Since the voltage $V$ applied is the same as the rated voltage,each bulb consumes its rated power.Therefore,$P_{	ext{total}} = P_1 + P_2$.

Two electric bulbs rated $P_1 \text{ watt}, V \text{ volt}$ and $P_2 \text{ watt}, V \text{ volt}$ are connected in parallel and $V \text{ volt}$ is applied to them. The total power consumed will be

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