A carrier wave of peak voltage 12 ,V is used | vedclass

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(C) The modulation index $\mu$ is defined as the ratio of the peak voltage of the modulating signal $(E_m)$ to the peak voltage of the carrier wave $(

Vedclass · Accepted Answer

$9$

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(C) The modulation index $\mu$ is defined as the ratio of the peak voltage of the modulating signal $(E_m)$ to the peak voltage of the carrier wave $(E_c)$.$\mu = \frac{E_m}{E_c}$Given:Carrier wave peak voltage $E_c = 12 \,V$Modulation index $\mu = 75 \% = 0.75 = \frac{3}{4}$Substituting the values into the formula:$0.75 = \frac{E_m}{12}$$E_m = 0.75 	imes 12$$E_m = 9 \,V$Therefore, the peak voltage of the modulating signal is $9 \,V$.

$A$ carrier wave of peak voltage $12 \,V$ is used to transmit a signal. If the modulation index is $75 \%$, the peak voltage of the modulating signal is (in $\,V$)

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