$A$ tangent $PT$ is drawn to the circle $x^2+y^2=4$ at the point $P(\sqrt{3}, 1)$. If a straight line $L$ which is perpendicular to $PT$ is a tangent to the circle $(x-3)^2+y^2=1$,then a possible equation of $L$ is

  • A
    $x-\sqrt{3}y=1$
  • B
    $x-\sqrt{3}y=4$
  • C
    $x-\sqrt{3}y=-1$
  • D
    $x-\sqrt{3}y=7$

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