$\lim _{x \rightarrow 0} \frac{x \tan 4x - 2x \tan 2x}{(1 - \cos 4x)^2} = $

  • A
    $\frac{1}{8}$
  • B
    $\frac{1}{4}$
  • C
    $\frac{1}{2}$
  • D
    $1$

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