$PQR$ is an isosceles triangle with $PQ=PR$. If the radius of the circumcircle of $\triangle PQR$ is equal to the length of $PQ$,then $\angle P=$ (in $^{\circ}$)

  • A
    $30$
  • B
    $60$
  • C
    $45$
  • D
    $120$

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