$\int_0^2 x^3(2-x)^4 \, dx = $

  • A
    $\frac{128}{105}$
  • B
    $\frac{16}{35}$
  • C
    $\frac{256}{105}$
  • D
    $\frac{32}{35}$

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Difficult
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$\int_1^3 \frac{\log x^2}{\log \left(16 x^2-8 x^3+x^4\right)} d x=\ldots$

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