$A$ short bar magnet of magnetic moment $2.5 \text{ Am}^2$ is kept in a uniform magnetic field of $4 \times 10^{-5} \text{ T}$. The work done in moving the magnet from its most stable position to its most unstable position is:

  • A
    $40 \times 10^{-5} \text{ J}$
  • B
    $25 \times 10^{-5} \text{ J}$
  • C
    $10 \times 10^{-5} \text{ J}$
  • D
    $20 \times 10^{-5} \text{ J}$

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