$A$ circular coil of area $2 \,cm^2$ has $1000$ turns. If the current through the coil is $1 \,A$, then its magnetic moment is (in $\,Am^2$)

What is the magnetic moment due to the given current distribution?

$A$ closely wound solenoid of $1000$ turns and area of cross-section $2 \times 10^{-4} \ m^2$ carrying a current of $5.0 \ A$. The magnetic moment is . . . . . . $A \ m^2$.

$A$ wire of length $314 \, cm$ carrying a current of $14 \, A$ is bent to form a circle. The magnetic moment of the coil is $........ \, A \cdot m^2$. [Given $\pi = 3.14$]

$A$ wire of length $L$ metre carrying a current of $I$ ampere is bent in the form of a circle. Its magnetic moment is:

Magnetic induction at the centre of a circular loop of area $\pi \ m^2$ is $0.1 \ T$. The magnetic moment of the loop is ( $\mu_0 = \text{permeability of air}$ ).