$A$ box contains $8$ red, $3$ white and $9$ blue balls. If $3$ balls are drawn from the box at random one after the other without replacement, then the probability that they are $2$ red balls and $1$ white ball is
- A$\frac{7}{95}$
- B$\frac{13}{95}$
- C$\frac{7}{36}$
- D$\frac{11}{36}$
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$A$ bag contains $6$ red, $2$ white and $8$ blue balls. Three balls are drawn at random from the bag. Match the items of List-$I$ with those of List-$II$.
$A$. Probability that none of the balls is white $I$. $\frac{1}{70}$ $B$. Probability of getting $2$ white and $1$ blue ball $II$. $\frac{6}{35}$ $C$. Probability of getting $2$ blue and $1$ white ball $III$. $\frac{13}{20}$ $D$. Probability of getting $1$ red, $1$ white and $1$ blue ball $IV$. $\frac{1}{10}$
| $A$. Probability that none of the balls is white | $I$. $\frac{1}{70}$ |
| $B$. Probability of getting $2$ white and $1$ blue ball | $II$. $\frac{6}{35}$ |
| $C$. Probability of getting $2$ blue and $1$ white ball | $III$. $\frac{13}{20}$ |
| $D$. Probability of getting $1$ red, $1$ white and $1$ blue ball | $IV$. $\frac{1}{10}$ |
Out of the first $5$ consecutive natural numbers,if two different numbers $x$ and $y$ are chosen at random,then the probability that $x^4 - y^4$ is divisible by $5$ is
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