$A$ number $n$ is chosen at random from $S=\{1, 2, 3, \ldots, 50\}$. Let $A=\{n \in S: n+\frac{50}{n} > 27\}$, $B=\{n \in S: n \text{ is a prime}\}$ and $C=\{n \in S: n \text{ is a square}\}$. Then, the correct order of their probabilities is:

  • A
    $P(A) < P(B) < P(C)$
  • B
    $P(A) > P(B) > P(C)$
  • C
    $P(B) < P(A) < P(C)$
  • D
    $P(A) > P(C) > P(B)$

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