A planet is revolving around the Sun in an el | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) According to Kepler's Second Law (Law of Areas), the radius vector joining the Sun and the planet sweeps out equal areas in equal intervals of tim

Vedclass · Accepted Answer

The time taken in travelling $DAB$ is less than that for $BCD$.

Vedclass · Answer

(A) According to Kepler's Second Law (Law of Areas), the radius vector joining the Sun and the planet sweeps out equal areas in equal intervals of time.In the given figure, the Sun $(S)$ is at one of the foci of the elliptical orbit.The area swept by the planet in path $DAB$ is the area of the region bounded by the arc $DAB$ and the lines $SD$ and $SB$.The area swept by the planet in path $BCD$ is the area of the region bounded by the arc $BCD$ and the lines $SB$ and $SD$.Since the Sun is closer to the side $A$, the area swept by the planet in path $DAB$ is smaller than the area swept in path $BCD$.Therefore, the time taken to travel $DAB$ is less than the time taken to travel $BCD$.

$A$ planet is revolving around the Sun in an elliptical orbit as shown in the figure. Which of the following is a correct statement?

Similar Questions

Assertion $(A)$: Angular speed,linear speed,and kinetic energy change with time,but angular momentum remains constant for a planet orbiting the sun.
Reason $(R)$: Angular momentum is constant as no external torque acts on the planet.

Assume that the earth moves around the sun in a circular orbit of radius $R$ and there exists a planet which also moves around the sun in a circular orbit with an angular speed twice as large as that of the earth. The radius of the orbit of the planet is

The period of revolution of planet $A$ around the sun is $8$ times that of $B$. The distance of $A$ from the sun is how many times greater than that of $B$ from the sun?

If $A$ is the areal velocity of a planet of mass $M$,its angular momentum is

The mean radius of the earth's orbit around the sun is $1.5 \times 10^{11} \ m$. The mean radius of the orbit of Mercury around the sun is $6 \times 10^{10} \ m$. Mercury will revolve around the sun in:

Vedclass Test Series

Exam Paper Generator

Online Exam Module