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(C) Step $1$: Calculate the time taken for free fall $(t_1)$ and velocity attained $(v)$.For free fall, initial velocity $u = 0$, distance $s_1 = 20 \

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$101$

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(C) Step $1$: Calculate the time taken for free fall $(t_1)$ and velocity attained $(v)$.For free fall, initial velocity $u = 0$, distance $s_1 = 20 \ m$, and $g = 10 \ m/s^2$.Using $v^2 = u^2 + 2gs_1$, we get $v^2 = 0 + 2 	imes 10 	imes 20 = 400$, so $v = 20 \ m/s$.Using $v = u + gt_1$, we get $20 = 0 + 10t_1$, so $t_1 = 2 \ s$.Step $2$: Calculate the time taken for uniform motion $(t_2)$.The remaining distance is $s_2 = 2000 \ m - 20 \ m = 1980 \ m$.The velocity is constant at $v = 20 \ m/s$.Time $t_2 = s_2 / v = 1980 / 20 = 99 \ s$.Step $3$: Calculate total time.Total time $T = t_1 + t_2 = 2 \ s + 99 \ s = 101 \ s$.

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