A particle is moving in a circle of radius 5 | vedclass

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Question

(A) Radius of the circle, $r = 5 \,cm$. Time period, $T = 5 \,s$. Angular velocity is given by $\omega = \frac{2 \pi}{T} = \frac{2 \pi}{5} \,rad/s$. L

Vedclass · Accepted Answer

$0.8 \pi^2 \,cm / s^2$

Vedclass · Answer

(A) Radius of the circle, $r = 5 \,cm$. Time period, $T = 5 \,s$. Angular velocity is given by $\omega = \frac{2 \pi}{T} = \frac{2 \pi}{5} \,rad/s$. Linear speed is $v = \omega r = (\frac{2 \pi}{5}) 	imes 5 = 2 \pi \,cm/s$. Since the particle is in uniform circular motion, the acceleration is centripetal acceleration, given by $a = \frac{v^2}{r}$. Substituting the values, $a = \frac{(2 \pi)^2}{5} = \frac{4 \pi^2}{5} = 0.8 \pi^2 \,cm/s^2$.

$A$ particle is moving in a circle of radius $5 \,cm$ with uniform speed and completes the circle in $5 \,s$. What is the magnitude of linear acceleration?

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