A point P is moving in uniform circular motio | vedclass

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(C) In uniform circular motion, the speed of the particle is constant. Therefore, the acceleration of the particle is purely centripetal, meaning it i

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$v \cdot a = 0$ and $r 	imes a = 0$

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(C) In uniform circular motion, the speed of the particle is constant. Therefore, the acceleration of the particle is purely centripetal, meaning it is directed towards the center of the circular path.Since the centripetal acceleration is always directed towards the center, it is always parallel to the position vector $r$ (measured from the center) and perpendicular to the velocity vector $v$ (which is tangential to the path).$1$. Because the acceleration $a$ is perpendicular to the velocity $v$, their dot product must be zero: $v \cdot a = 0$.$2$. Because the acceleration $a$ is directed towards the center, it is collinear with the position vector $r$. Two vectors that are collinear (parallel or anti-parallel) have a cross product equal to zero: $r 	imes a = 0$.Thus, the correct statement is $v \cdot a = 0$ and $r 	imes a = 0$.

$A$ point $P$ is moving in uniform circular motion with radius $3 \ m$. Let at some instant the acceleration of the point be $a = (6 \hat{i} - 4 \hat{j}) \ m/s^2$, the position vector be $r$, and the velocity vector be $v$. Choose the correct statement.

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