A Zener diode with a Zener voltage of 30 text | vedclass

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(A) Step $1$: Current through Load Resistor $(I_L)$Since the Zener diode regulates the voltage at $30 	ext{ V}$, the voltage across the load resistor

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$5$

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(A) Step $1$: Current through Load Resistor $(I_L)$Since the Zener diode regulates the voltage at $30 	ext{ V}$, the voltage across the load resistor $(R_L = 6 	ext{ k}\Omega)$ will also be $30 	ext{ V}$.The current through the load resistor, $I_L$, is:$I_L = \frac{V_Z}{R_L} = \frac{30 	ext{ V}}{6 	ext{ k}\Omega} = 5 	ext{ mA}$Step $2$: Total Current in the Circuit $(I_{	ext{total}})$The total current supplied by the source, $I_{	ext{total}}$, is given by:$I_{	ext{total}} = \frac{V_{	ext{in}} - V_Z}{R_{	ext{total}}}$where $R_{	ext{total}} = 5 	ext{ k}\Omega + 2 	ext{ k}\Omega = 7 	ext{ k}\Omega$.For maximum $I_{	ext{total}}$, we use the maximum input voltage $V_{	ext{in}} = 100 	ext{ V}$:$I_{	ext{total}} = \frac{100 	ext{ V} - 30 	ext{ V}}{7 	ext{ k}\Omega} = \frac{70 	ext{ V}}{7 	ext{ k}\Omega} = 10 	ext{ mA}$Step $3$: Maximum Zener Diode Current $(I_{Z \max})$The Zener diode current $I_Z$ is the difference between the total current and the load current:$I_{Z \max} = I_{	ext{total}} - I_L = 10 	ext{ mA} - 5 	ext{ mA} = 5 	ext{ mA}$Final Answer:The maximum current through the Zener diode is $5 	ext{ mA}$.

$A$ Zener diode with a Zener voltage of $30 \text{ V}$ is connected in a circuit as shown in the figure. The maximum current through the Zener diode is: (in $\text{ mA}$)

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