(B) The density $\rho$ of a unit cell is given by $\rho = \frac{Z \times M}{N_A \times a^3}$.For the $\alpha$-form $(fcc)$: $Z_1 = 4$, $a_1 = 2 \ pm$.

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(B) The density $\rho$ of a unit cell is given by $\rho = \frac{Z \times M}{N_A \times a^3}$.For the $\alpha$-form $(fcc)$: $Z_1 = 4$, $a_1 = 2 \ pm$.For the $\beta$-form $(bcc)$: $Z_2 = 2$, $a_2 = 4 \ pm$.The ratio of densities is $\frac{\rho_\alpha}{\rho_\beta} = \frac{Z_1}{Z_2} \times \left(\frac{a_2}{a_1}\right)^3$.Substituting the values: $\frac{\rho_\alpha}{\rho_\beta} = \frac{4}{2} \times \left(\frac{4}{2}\right)^3 = 2 \times (2)^3 = 2 \times 8 = 16$.

Class 12 Chemistry Solid State Mathematical analysis of cubic system and Bragg’s equation

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$A$ compound can crystallise in two forms $\alpha$ and $\beta$ which are $fcc$ and $bcc$, respectively. The $\alpha$-form has a side length of $2 \ pm$ and the $\beta$-form has a side length of $4 \ pm$. The ratio of their density $\frac{\rho_\alpha}{\rho_\beta}$ is

TS EAMCET 2020 All TS EAMCET

A
$32$
B
$16$
C
$8$
D
$4$

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Mathematical analysis of cubic system and Bragg’s equation

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$A$ compound can crystallise in two forms $\alpha$ and $\beta$ which are $fcc$ and $bcc$, respectively. The $\alpha$-form has a side length of $2 \ pm$ and the $\beta$-form has a side length of $4 \ pm$. The ratio of their density $\frac{\rho_\alpha}{\rho_\beta}$ is

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An element (atomic mass $100 \ g/mol$) having $bcc$ structure has unit cell edge $400 \ pm$. Then density of the element is (in $g/cm^3$)

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