A piece of length 3.532 m is cut from a rod | vedclass

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Question

(A) The length of the original rod is $43.4 \ m$ (which has $3$ significant figures and is precise up to the first decimal place).The length of the pi

Vedclass · Accepted Answer

$39.9$

Vedclass · Answer

(A) The length of the original rod is $43.4 \ m$ (which has $3$ significant figures and is precise up to the first decimal place).The length of the piece cut is $3.532 \ m$ (which has $4$ significant figures and is precise up to the third decimal place).When subtracting, the result should be reported to the same number of decimal places as the measurement with the fewest decimal places.Remaining length $= 43.4 \ m - 3.532 \ m = 39.868 \ m$.Since $43.4$ has only one decimal place, we must round the result to one decimal place.Rounding $39.868$ to one decimal place gives $39.9 \ m$.

Column-$I$	Column-$II$
$(a)$ $0.007\ m^2$	$(p)$ $2$
$(b)$ $2.64 \times 10^{24}\ kg$	$(q)$ $1$
$(c)$ $0.0021\ g\ cm^{-3}$	$(r)$ $4$
$(d)$ $0.0006032\ J$	$(s)$ $3$

$A$ piece of length $3.532 \ m$ is cut from a rod of length $43.4 \ m$. The length of the remaining rod in metre is (up to correct significant figures)

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Three measurements are made as $18.425 \, cm$,$7.21 \, cm$,and $5.0 \, cm$. The addition should be written as ........ $cm$.

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Column-$I$ Column-$II$

$(a)$ $0.007\ m^2$ $(p)$ $2$

$(b)$ $2.64 \times 10^{24}\ kg$ $(q)$ $1$

$(c)$ $0.0021\ g\ cm^{-3}$ $(r)$ $4$

$(d)$ $0.0006032\ J$ $(s)$ $3$

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