A ball of mass 0.2 kg moving with a speed of | vedclass

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(C) Given: Mass $m = 0.2 \ kg$, initial velocity $u = 20 \ m s^{-1}$, final velocity $v = 0 \ m s^{-1}$, and time $t = 0.1 \ s$.Using the impulse-mome

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$40$

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(C) Given: Mass $m = 0.2 \ kg$, initial velocity $u = 20 \ m s^{-1}$, final velocity $v = 0 \ m s^{-1}$, and time $t = 0.1 \ s$.Using the impulse-momentum theorem or Newton's second law, the average force $F$ is given by the rate of change of momentum:$F = \frac{\Delta p}{\Delta t} = \frac{m(v - u)}{t}$Substituting the values:$F = \frac{0.2 	imes (0 - 20)}{0.1}$$F = \frac{0.2 	imes (-20)}{0.1}$$F = \frac{-4}{0.1} = -40 \ N$The magnitude of the average force applied to the ball is $40 \ N$.

$A$ ball of mass $0.2 \ kg$ moving with a speed of $20 \ m s^{-1}$ is brought to rest in $0.1 \ s$. The average force applied to the ball is (in $N$)

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