A shell of mass 5 M, acted upon by no externa | vedclass

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(C) Let the velocity of the third fragment be $v'$.According to the law of conservation of linear momentum, since no external force acts on the system

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be at rest

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(C) Let the velocity of the third fragment be $v'$.According to the law of conservation of linear momentum, since no external force acts on the system, the total initial momentum is equal to the total final momentum.Initial momentum $P_i = 5 M 	imes 0 = 0$.Let the velocity of the first fragment $(M)$ be $\vec{v}_1 = 2v \hat{i}$ and the velocity of the second fragment $(2M)$ be $\vec{v}_2 = -v \hat{i}$ (since they move in opposite directions).Final momentum $P_f = M(2v \hat{i}) + 2M(-v \hat{i}) + 2M(\vec{v}') = 0$.$2Mv \hat{i} - 2Mv \hat{i} + 2M(\vec{v}') = 0$.$0 + 2M(\vec{v}') = 0$.Therefore, $\vec{v}' = 0$.The third fragment will be at rest.

$A$ shell of mass $5 M$, acted upon by no external force and initially at rest, bursts into three fragments of masses $M, 2 M$, and $2 M$ respectively. The first two fragments move in opposite directions with velocities of magnitudes $2 v$ and $v$ respectively. The third fragment will

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