$_{11}Na^{24}$ is radioactive and it decays to

  • A
    $_{9}F^{20}$ and $\alpha$-particles
  • B
    $_{13}Al^{24}$ and positron
  • C
    $_{11}Na^{23}$ and neutron
  • D
    $_{12}Mg^{24}$ and $\beta$-particles

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The number of neutrons in the parent nucleus which gives $N^{14}$ on $\beta$-emission and the parent nucleus is

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