An atomic nucleus having a low n/p ratio trie | vedclass

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(B) Nuclei with a low $n/p$ ratio are proton-rich and unstable. They achieve stability by increasing the $n/p$ ratio. This can occur through two prima

Vedclass · Accepted Answer

the emission of a positron

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(B) Nuclei with a low $n/p$ ratio are proton-rich and unstable. They achieve stability by increasing the $n/p$ ratio. This can occur through two primary processes: $1$. Positron emission: $^1_1p ightarrow ^1_0n + ^0_{+1}e + 
u$ $2$. $K$-electron capture: $^1_1p + ^0_{-1}e ightarrow ^1_0n + 
u$ Both processes convert a proton into a neutron, thereby decreasing the number of protons and increasing the number of neutrons, which increases the $n/p$ ratio. Since both options $(B)$ and $(C)$ are correct, in many contexts, positron emission is the primary answer provided for this specific question type.

An atomic nucleus having a low $n/p$ ratio tries to find stability by:

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