$A$ conductivity cell has been calibrated with $0.01 \ M$ $1:1$ electrolyte solution (specific conductance, $k = 1.25 \times 10^{-3} \ S \ cm^{-1}$) in the cell and the measured resistance was $800 \ \Omega$ at $25^{\circ}C$. The cell constant will be (in $cm^{-1}$)

Limiting molar conductivity of $NH_4OH$ [i.e.,$\Lambda ^o_{m(NH_4OH)}$] is equal to:

The specific conductivity of a normal solution of $KCl$ at $25 \, ^oC$ is $0.002765 \, S \, cm^{-1}$. If the resistance of the cell is $400 \, \Omega$,what is the cell constant (in $cm^{-1}$)?

Given below is the plot of the molar conductivity vs $\sqrt{concentration}$ for $KCl$ in aqueous solution. If,for the higher concentration of $KCl$ solution,the resistance of the conductivity cell is $100 \ \Omega$,then the resistance of the same cell with the dilute solution is '$x$' $\Omega$. The value of $x$ is $............$ ($Nearest$ $integer$)

The conductivity of a solution containing $2.08 \ g$ of anhydrous barium chloride in $200 \ mL$ solution is $6 \times 10^{-3} \ \Omega^{-1} \ cm^{-1}$. The molar conductivity of the solution (in $\Omega^{-1} \ cm^2 \ mol^{-1}$) is $\underline{x} \times 10^2$. The value of $\underline{x}$ is (Atomic mass of $Ba=137, Cl=35.5$)

What is the molar conductivity of a $0.05 \ M$ solution of sodium hydroxide,if its conductivity is $0.0118 \ S \ cm^{-1}$ at $298 \ K$?