The specific conductivity of a normal solution of $KCl$ at $25 \, ^oC$ is $0.002765 \, S \, cm^{-1}$. If the resistance of the cell is $400 \, \Omega$,what is the cell constant (in $cm^{-1}$)?

  • A
    $0.815$
  • B
    $1.016$
  • C
    $1.106$
  • D
    $2.016$

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At $25\,^{\circ}C$,the specific conductivity of a normal solution of $KCl$ is $0.002765\,S\,cm^{-1}$. The resistance of the cell is $400\,\Omega$. The cell constant is: (in $,cm^{-1}$)

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