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(B, D) According to Faraday's law of electromagnetic induction, an emf is induced in a loop when the magnetic flux $\Phi = B \cdot A \cos 	heta$ link

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rotated about one of its diameters

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(B, D) According to Faraday's law of electromagnetic induction, an emf is induced in a loop when the magnetic flux $\Phi = B \cdot A \cos 	heta$ linked with the loop changes with time.$1$. If the loop is moved along the direction of $B$, the magnetic field $B$, area $A$, and the angle $	heta$ remain constant. Thus, the flux remains constant, and no emf is induced.$2$. If the loop is squeezed to a smaller area, the area $A$ changes with time. Therefore, the magnetic flux $\Phi$ changes, and an emf is induced.$3$. If the loop is rotated about its axis, the orientation of the area vector relative to the magnetic field remains constant $(	heta = 0^\circ)$. Thus, the flux remains constant, and no emf is induced.$4$. If the loop is rotated about one of its diameters, the angle $	heta$ between the magnetic field $B$ and the area vector changes with time. Therefore, the magnetic flux $\Phi$ changes, and an emf is induced.Since both $(b)$ and $(d)$ result in a change in magnetic flux, both conditions will induce an emf.

$A$ metallic loop is placed in a uniform magnetic field $B$ with the plane of the loop perpendicular to $B$. Under which condition will an electromotive force (emf) be induced in the loop? "If the loop is ....."

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