A box of mass 2 kg is placed on the roof of a | vedclass

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(D) Given: Mass of the box $m = 2 kg$, coefficient of static friction $\mu = 0.2$, and acceleration due to gravity $g = 10 ms^{-2}$.For the box to rem

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$2$

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(D) Given: Mass of the box $m = 2 kg$, coefficient of static friction $\mu = 0.2$, and acceleration due to gravity $g = 10 ms^{-2}$.For the box to remain stationary on the roof of the car, the pseudo-force acting on the box must be balanced by the static frictional force.The maximum static frictional force is given by $f_{max} = \mu N = \mu mg$.The force required to accelerate the box with the car is $F = ma$.Equating the two, we get $ma = \mu mg$.Therefore, $a = \mu g$.Substituting the values: $a = 0.2 	imes 10 = 2 ms^{-2}$.Thus, the maximum acceleration of the car is $2 ms^{-2}$.

Similar Questions

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