PbCl_{2} is insoluble in cold water. Addition | vedclass

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Question

(A) $PbCl_{2}$ is sparingly soluble in cold water. Upon adding $HCl$, the excess $Cl^{-}$ ions react with $PbCl_{2}$ to form soluble complex anions.Th

Vedclass · Accepted Answer

formation of soluble complex anions like $[PbCl_{3}]^{-}$

Vedclass · Answer

(A) $PbCl_{2}$ is sparingly soluble in cold water. Upon adding $HCl$, the excess $Cl^{-}$ ions react with $PbCl_{2}$ to form soluble complex anions.The reaction is as follows:$PbCl_{2(s)} + Cl^{-} \rightarrow [PbCl_{3}]^{-}_{(aq)}$$PbCl_{2(s)} + 2Cl^{-} \rightarrow [PbCl_{4}]^{2-}_{(aq)}$These complex ions are soluble in water, which increases the overall solubility of $PbCl_{2}$ in the presence of $HCl$.

$PbCl_{2}$ is insoluble in cold water. Addition of $HCl$ increases its solubility due to

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