A ray of light strikes a glass plate at an an | vedclass

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(D) Given that the angle of incidence $i = 60^{\circ}$.According to Brewster's law, when the reflected and refracted rays are perpendicular to each ot

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$\sqrt{3}$

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(D) Given that the angle of incidence $i = 60^{\circ}$.According to Brewster's law, when the reflected and refracted rays are perpendicular to each other, the angle of incidence is the polarizing angle $(i_p)$.From Snell's law, $\mu = \frac{\sin i}{\sin r}$.Since the reflected and refracted rays are perpendicular, the angle between them is $90^{\circ}$.From the geometry of the setup, $i + 90^{\circ} + r = 180^{\circ}$, which gives $r = 90^{\circ} - i$.Substituting this into Snell's law:$\mu = \frac{\sin i}{\sin(90^{\circ} - i)} = \frac{\sin i}{\cos i} = 	an i$.Given $i = 60^{\circ}$, we have $\mu = 	an 60^{\circ} = \sqrt{3}$.

$A$ ray of light strikes a glass plate at an angle of $60^{\circ}$. If the reflected and refracted rays are perpendicular to each other, the refractive index of glass is

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