$\lim _{n \rightarrow \infty} \frac{1}{n^{k+1}}\left[2^k+4^k+6^k+\ldots+(2 n)^k\right]=$

  • A
    $\frac{2^k}{k}$
  • B
    $\frac{2^{k+1}}{k+1}$
  • C
    $\frac{2^k}{k+1}$
  • D
    $\frac{2^k}{k-1}$

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