$A$ bag contains $10$ balls out of which $k$ are red and $(10-k)$ are black, where $0 \le k \le 10$. If three balls are drawn at random without replacement and all of them are found to be black, then the probability that the bag contains $1$ red and $9$ black balls is:

  • A
    $\frac{7}{11}$
  • B
    $\frac{7}{55}$
  • C
    $\frac{7}{110}$
  • D
    $\frac{14}{55}$

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