A large drum having radius R is spinning arou | vedclass

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(D) For the body of mass $M$ to remain stuck to the inner wall of the rotating drum, the normal force $N$ exerted by the wall provides the necessary c

Vedclass · Accepted Answer

$\sqrt{\frac{g}{\mu R}}$

Vedclass · Answer

(D) For the body of mass $M$ to remain stuck to the inner wall of the rotating drum, the normal force $N$ exerted by the wall provides the necessary centripetal force: $N = M \omega^2 R$ The frictional force $f$ acts vertically upwards to balance the gravitational force $Mg$ acting downwards: $f = Mg$ Since the body is on the verge of slipping, the frictional force is at its maximum value, given by $f = \mu N$: $Mg = \mu N$ Substituting the expression for $N$ into the friction equation: $Mg = \mu (M \omega^2 R)$ Dividing both sides by $M$ and solving for $\omega$: $g = \mu \omega^2 R$ $\omega^2 = \frac{g}{\mu R}$ $\omega = \sqrt{\frac{g}{\mu R}}$

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