$A$ displacement current of $4.0 \text{ A}$ can be set up in the space between two parallel plates of a $6 \text{ }\mu\text{F}$ capacitor. The rate of change of potential difference across the plates of the capacitor is nearly $\alpha \times 10^6 \text{ V/s}$. The value of $\alpha$ is . . . . . . .

At a particular instant,the current in the circuit given below is $i$. The displacement current between the plates of the capacitor shown below is ..........

Write the $SI$ unit of ${\epsilon _0}\left( {\frac{{d{\Phi _E}}}{{dt}}} \right)$.

$A$ parallel-plate capacitor with circular plates is being discharged. The radius of the circular plates is $10 \ cm$. $A$ circular loop of radius $20 \ cm$ is concentric with the capacitor and located halfway between the plates. If the electric field between the plates is changing at the rate of $3.6 \times 10^{12} \ V/(m \cdot s)$,then the displacement current through the loop is (Assume $\frac{1}{4 \pi \varepsilon_0} = 9 \times 10^9 \ N \cdot m^2/C^2$) (in $A$)

What are Maxwell's equations? Write these equations.

$A$ variable frequency $AC$ source is connected to a capacitor. How will the displacement current change with a decrease in frequency?