A box of mass 15 text{ kg} is kept on the flo | vedclass

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(B) The limiting frictional force $f_s$ provides the necessary force for the box to accelerate along with the trolley.For the box to remain stationary

Vedclass · Accepted Answer

$1.2$

Vedclass · Answer

(B) The limiting frictional force $f_s$ provides the necessary force for the box to accelerate along with the trolley.For the box to remain stationary relative to the trolley, the pseudo force acting on the box must be balanced by the static frictional force.The condition for the box to remain stationary on the trolley is: $ma \le f_{s, 	ext{max}}$.Since $f_{s, 	ext{max}} = \mu N = \mu mg$, we have $ma \le \mu mg$.This simplifies to $a \le \mu g$.Given $\mu = 0.12$ and $g = 10 	ext{m s}^{-2}$, the maximum acceleration $a_{	ext{max}} = \mu g = 0.12 	imes 10 = 1.2 	ext{m s}^{-2}$.Therefore, the maximum acceleration with which the trolley can be moved is $1.2 	ext{m s}^{-2}$.

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