$A$ car is travelling at $40\text{ m/s}$ on a circular path of radius $40\text{ m}$. It is increasing its speed at the rate of $2\text{ m/s}^2$. Its net acceleration is (in $\text{m/s}^2$) nearly (in $\text{ m/s}^2$)

$A$ point $P$ moves in a counter-clockwise direction on a circular path as shown in the figure. The movement of $P$ is such that it sweeps out a length $s = t^3 + 5$,where $s$ is in meters and $t$ is in seconds. The radius of the path is $20 \ m$. The acceleration of $P$ when $t = 2 \ s$ is nearly .......... $m/s^2$.

$A$ particle is confined to rotate in a circular path with decreasing linear speed. Which of the following is correct?

The distance of a particle moving on a circle of radius $12 \, m$ measured from a fixed point on the circle and measured along the circle is given by $s = 2t^3$ (in meters). The ratio of its tangential to centripetal acceleration at $t = 2 \, s$ is .........

If the radius of curvature of the path of two particles of same mass are in the ratio $3:4,$ then in order to have constant centripetal force,their velocities will be in the ratio of:

$A$ particle moves on a circular path with decreasing speed. Identify the correct statement.